2x^2-4x+800=0

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Solution for 2x^2-4x+800=0 equation: 



2x^2-4x+800=0

a = 2; b = -4; c = +800;
Δ = b2-4ac
Δ = -42-4·2·800
Δ = -6384
Delta is less than zero, so there is no solution for the equation

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